LeastSquares.h 6.77 KB
Newer Older
LM's avatar
LM committed
1
// This file is part of Eigen, a lightweight C++ template library
Don Gagne's avatar
Don Gagne committed
2
// for linear algebra.
LM's avatar
LM committed
3 4 5
//
// Copyright (C) 2006-2009 Benoit Jacob <jacob.benoit.1@gmail.com>
//
Don Gagne's avatar
Don Gagne committed
6 7 8
// This Source Code Form is subject to the terms of the Mozilla
// Public License v. 2.0. If a copy of the MPL was not distributed
// with this file, You can obtain one at http://mozilla.org/MPL/2.0/.
LM's avatar
LM committed
9 10 11 12

#ifndef EIGEN2_LEASTSQUARES_H
#define EIGEN2_LEASTSQUARES_H

Don Gagne's avatar
Don Gagne committed
13 14
namespace Eigen { 

LM's avatar
LM committed
15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166
/** \ingroup LeastSquares_Module
  *
  * \leastsquares_module
  *
  * For a set of points, this function tries to express
  * one of the coords as a linear (affine) function of the other coords.
  *
  * This is best explained by an example. This function works in full
  * generality, for points in a space of arbitrary dimension, and also over
  * the complex numbers, but for this example we will work in dimension 3
  * over the real numbers (doubles).
  *
  * So let us work with the following set of 5 points given by their
  * \f$(x,y,z)\f$ coordinates:
  * @code
    Vector3d points[5];
    points[0] = Vector3d( 3.02, 6.89, -4.32 );
    points[1] = Vector3d( 2.01, 5.39, -3.79 );
    points[2] = Vector3d( 2.41, 6.01, -4.01 );
    points[3] = Vector3d( 2.09, 5.55, -3.86 );
    points[4] = Vector3d( 2.58, 6.32, -4.10 );
  * @endcode
  * Suppose that we want to express the second coordinate (\f$y\f$) as a linear
  * expression in \f$x\f$ and \f$z\f$, that is,
  * \f[ y=ax+bz+c \f]
  * for some constants \f$a,b,c\f$. Thus, we want to find the best possible
  * constants \f$a,b,c\f$ so that the plane of equation \f$y=ax+bz+c\f$ fits
  * best the five above points. To do that, call this function as follows:
  * @code
    Vector3d coeffs; // will store the coefficients a, b, c
    linearRegression(
      5,
      &points,
      &coeffs,
      1 // the coord to express as a function of
        // the other ones. 0 means x, 1 means y, 2 means z.
    );
  * @endcode
  * Now the vector \a coeffs is approximately
  * \f$( 0.495 ,  -1.927 ,  -2.906 )\f$.
  * Thus, we get \f$a=0.495, b = -1.927, c = -2.906\f$. Let us check for
  * instance how near points[0] is from the plane of equation \f$y=ax+bz+c\f$.
  * Looking at the coords of points[0], we see that:
  * \f[ax+bz+c = 0.495 * 3.02 + (-1.927) * (-4.32) + (-2.906) = 6.91.\f]
  * On the other hand, we have \f$y=6.89\f$. We see that the values
  * \f$6.91\f$ and \f$6.89\f$
  * are near, so points[0] is very near the plane of equation \f$y=ax+bz+c\f$.
  *
  * Let's now describe precisely the parameters:
  * @param numPoints the number of points
  * @param points the array of pointers to the points on which to perform the linear regression
  * @param result pointer to the vector in which to store the result.
                  This vector must be of the same type and size as the
                  data points. The meaning of its coords is as follows.
                  For brevity, let \f$n=Size\f$,
                  \f$r_i=result[i]\f$,
                  and \f$f=funcOfOthers\f$. Denote by
                  \f$x_0,\ldots,x_{n-1}\f$
                  the n coordinates in the n-dimensional space.
                  Then the resulting equation is:
                  \f[ x_f = r_0 x_0 + \cdots + r_{f-1}x_{f-1}
                   + r_{f+1}x_{f+1} + \cdots + r_{n-1}x_{n-1} + r_n. \f]
  * @param funcOfOthers Determines which coord to express as a function of the
                        others. Coords are numbered starting from 0, so that a
                        value of 0 means \f$x\f$, 1 means \f$y\f$,
                        2 means \f$z\f$, ...
  *
  * \sa fitHyperplane()
  */
template<typename VectorType>
void linearRegression(int numPoints,
                      VectorType **points,
                      VectorType *result,
                      int funcOfOthers )
{
  typedef typename VectorType::Scalar Scalar;
  typedef Hyperplane<Scalar, VectorType::SizeAtCompileTime> HyperplaneType;
  const int size = points[0]->size();
  result->resize(size);
  HyperplaneType h(size);
  fitHyperplane(numPoints, points, &h);
  for(int i = 0; i < funcOfOthers; i++)
    result->coeffRef(i) = - h.coeffs()[i] / h.coeffs()[funcOfOthers];
  for(int i = funcOfOthers; i < size; i++)
    result->coeffRef(i) = - h.coeffs()[i+1] / h.coeffs()[funcOfOthers];
}

/** \ingroup LeastSquares_Module
  *
  * \leastsquares_module
  *
  * This function is quite similar to linearRegression(), so we refer to the
  * documentation of this function and only list here the differences.
  *
  * The main difference from linearRegression() is that this function doesn't
  * take a \a funcOfOthers argument. Instead, it finds a general equation
  * of the form
  * \f[ r_0 x_0 + \cdots + r_{n-1}x_{n-1} + r_n = 0, \f]
  * where \f$n=Size\f$, \f$r_i=retCoefficients[i]\f$, and we denote by
  * \f$x_0,\ldots,x_{n-1}\f$ the n coordinates in the n-dimensional space.
  *
  * Thus, the vector \a retCoefficients has size \f$n+1\f$, which is another
  * difference from linearRegression().
  *
  * In practice, this function performs an hyper-plane fit in a total least square sense
  * via the following steps:
  *  1 - center the data to the mean
  *  2 - compute the covariance matrix
  *  3 - pick the eigenvector corresponding to the smallest eigenvalue of the covariance matrix
  * The ratio of the smallest eigenvalue and the second one gives us a hint about the relevance
  * of the solution. This value is optionally returned in \a soundness.
  *
  * \sa linearRegression()
  */
template<typename VectorType, typename HyperplaneType>
void fitHyperplane(int numPoints,
                   VectorType **points,
                   HyperplaneType *result,
                   typename NumTraits<typename VectorType::Scalar>::Real* soundness = 0)
{
  typedef typename VectorType::Scalar Scalar;
  typedef Matrix<Scalar,VectorType::SizeAtCompileTime,VectorType::SizeAtCompileTime> CovMatrixType;
  EIGEN_STATIC_ASSERT_VECTOR_ONLY(VectorType)
  ei_assert(numPoints >= 1);
  int size = points[0]->size();
  ei_assert(size+1 == result->coeffs().size());

  // compute the mean of the data
  VectorType mean = VectorType::Zero(size);
  for(int i = 0; i < numPoints; ++i)
    mean += *(points[i]);
  mean /= numPoints;

  // compute the covariance matrix
  CovMatrixType covMat = CovMatrixType::Zero(size, size);
  for(int i = 0; i < numPoints; ++i)
  {
    VectorType diff = (*(points[i]) - mean).conjugate();
    covMat += diff * diff.adjoint();
  }

  // now we just have to pick the eigen vector with smallest eigen value
  SelfAdjointEigenSolver<CovMatrixType> eig(covMat);
  result->normal() = eig.eigenvectors().col(0);
  if (soundness)
    *soundness = eig.eigenvalues().coeff(0)/eig.eigenvalues().coeff(1);

  // let's compute the constant coefficient such that the
  // plane pass trough the mean point:
  result->offset() = - (result->normal().cwise()* mean).sum();
}

Don Gagne's avatar
Don Gagne committed
167
} // end namespace Eigen
LM's avatar
LM committed
168 169

#endif // EIGEN2_LEASTSQUARES_H