# Copyright 2010 Hakan Kjellerstrand hakank@gmail.com # # Licensed under the Apache License, Version 2.0 (the "License"); # you may not use this file except in compliance with the License. # You may obtain a copy of the License at # # http://www.apache.org/licenses/LICENSE-2.0 # # Unless required by applicable law or agreed to in writing, software # distributed under the License is distributed on an "AS IS" BASIS, # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. # See the License for the specific language governing permissions and # limitations under the License. """ Olympic puzzle in Google CP Solver. Benchmark for Prolog (BProlog) ''' File : olympic.pl Author : Neng-Fa ZHOU Date : 1993 Purpose: solve a puzzle taken from Olympic Arithmetic Contest Given ten variables with the following configuration: X7 X8 X9 X10 X4 X5 X6 X2 X3 X1 We already know that X1 is equal to 3 and want to assign each variable with a different integer from {1,2,...,10} such that for any three variables Xi Xj Xk the following constraint is satisfied: |Xi-Xj| = Xk ''' Compare with the following models: * MiniZinc: http://www.hakank.org/minizinc/olympic.mzn * SICStus Prolog: http://www.hakank.org/sicstus/olympic.pl * ECLiPSe: http://hakank.org/eclipse/olympic.ecl * Gecode: http://hakank.org/gecode/olympic.cpp This model was created by Hakan Kjellerstrand (hakank@gmail.com) Also see my other Google CP Solver models: http://www.hakank.org/google_or_tools/ """ from __future__ import print_function import sys from ortools.constraint_solver import pywrapcp def minus(solver, x, y, z): solver.Add(z == abs(x - y)) def main(): # Create the solver. solver = pywrapcp.Solver('Olympic') # # data # n = 10 # # declare variables # Vars = [solver.IntVar(1, n, 'Vars[%i]' % i) for i in range(n)] X1, X2, X3, X4, X5, X6, X7, X8, X9, X10 = Vars # # constraints # solver.Add(solver.AllDifferent(Vars)) solver.Add(X1 == 3) minus(solver, X2, X3, X1) minus(solver, X4, X5, X2) minus(solver, X5, X6, X3) minus(solver, X7, X8, X4) minus(solver, X8, X9, X5) minus(solver, X9, X10, X6) # # solution and search # db = solver.Phase(Vars, solver.INT_VAR_SIMPLE, solver.INT_VALUE_DEFAULT) solver.NewSearch(db) num_solutions = 0 while solver.NextSolution(): num_solutions += 1 print('Vars:', [Vars[i].Value() for i in range(n)]) print() print('num_solutions:', num_solutions) print('failures:', solver.Failures()) print('branches:', solver.Branches()) print('WallTime:', solver.WallTime(), 'ms') if __name__ == '__main__': main()