// Copyright 2011 Hakan Kjellerstrand hakank@gmail.com // Licensed under the Apache License, Version 2.0 (the "License"); // you may not use this file except in compliance with the License. // You may obtain a copy of the License at // // http://www.apache.org/licenses/LICENSE-2.0 // // Unless required by applicable law or agreed to in writing, software // distributed under the License is distributed on an "AS IS" BASIS, // WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. // See the License for the specific language governing permissions and // limitations under the License. package com.google.ortools.examples; import com.google.ortools.constraintsolver.DecisionBuilder; import com.google.ortools.constraintsolver.IntVar; import com.google.ortools.constraintsolver.Solver; import java.io.*; import java.text.*; import java.util.*; public class DeBruijn { static { System.loadLibrary("jniortools"); } /** * toNum(solver, a, num, base) * *

channelling between the array a and the number num */ private static void toNum(Solver solver, IntVar[] a, IntVar num, int base) { int len = a.length; IntVar[] tmp = new IntVar[len]; for (int i = 0; i < len; i++) { tmp[i] = solver.makeProd(a[i], (int) Math.pow(base, (len - i - 1))).var(); } solver.addConstraint(solver.makeEquality(solver.makeSum(tmp).var(), num)); } /** * Implements "arbitrary" de Bruijn sequences. See * http://www.hakank.org/google_or_tools/debruijn_binary.py */ private static void solve(int base, int n, int m) { Solver solver = new Solver("DeBruijn"); System.out.println("base: " + base + " n: " + n + " m: " + m); // Ensure that the number of each digit in bin_code is // the same. Nice feature, but it can slow things down... boolean check_same_gcc = false; // true; // // variables // IntVar[] x = solver.makeIntVarArray(m, 0, (int) Math.pow(base, n) - 1, "x"); IntVar[][] binary = new IntVar[m][n]; for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { binary[i][j] = solver.makeIntVar(0, base - 1, "binary[" + i + "," + j + "]"); } } // this is the de Bruijn sequence IntVar[] bin_code = solver.makeIntVarArray(m, 0, base - 1, "bin_code"); // occurences of each number in bin_code IntVar[] gcc = solver.makeIntVarArray(base, 0, m, "gcc"); // for the branching IntVar[] all = new IntVar[2 * m + base]; for (int i = 0; i < m; i++) { all[i] = x[i]; all[m + i] = bin_code[i]; } for (int i = 0; i < base; i++) { all[2 * m + i] = gcc[i]; } // // constraints // solver.addConstraint(solver.makeAllDifferent(x)); // converts x <-> binary for (int i = 0; i < m; i++) { IntVar[] t = new IntVar[n]; for (int j = 0; j < n; j++) { t[j] = binary[i][j]; } toNum(solver, t, x[i], base); } // the de Bruijn condition: // the first elements in binary[i] is the same as the last // elements in binary[i-1] for (int i = 1; i < m; i++) { for (int j = 1; j < n; j++) { solver.addConstraint(solver.makeEquality(binary[i - 1][j], binary[i][j - 1])); } } // ... and around the corner for (int j = 1; j < n; j++) { solver.addConstraint(solver.makeEquality(binary[m - 1][j], binary[0][j - 1])); } // converts binary -> bin_code (de Bruijn sequence) for (int i = 0; i < m; i++) { solver.addConstraint(solver.makeEquality(bin_code[i], binary[i][0])); } // extra: ensure that all the numbers in the de Bruijn sequence // (bin_code) has the same occurrences (if check_same_gcc is True // and mathematically possible) solver.addConstraint(solver.makeDistribute(bin_code, gcc)); if (check_same_gcc && m % base == 0) { for (int i = 1; i < base; i++) { solver.addConstraint(solver.makeEquality(gcc[i], gcc[i - 1])); } } // symmetry breaking: // the minimum value of x should be first solver.addConstraint(solver.makeEquality(x[0], solver.makeMin(x).var())); // // search // DecisionBuilder db = solver.makePhase(all, solver.CHOOSE_MIN_SIZE_LOWEST_MAX, solver.ASSIGN_MIN_VALUE); solver.newSearch(db); // // output // while (solver.nextSolution()) { System.out.print("x: "); for (int i = 0; i < m; i++) { System.out.print(x[i].value() + " "); } System.out.print("\nde Bruijn sequence:"); for (int i = 0; i < m; i++) { System.out.print(bin_code[i].value() + " "); } System.out.print("\ngcc: "); for (int i = 0; i < base; i++) { System.out.print(gcc[i].value() + " "); } System.out.println("\n"); // for debugging etc: show the full binary table /* System.out.println("binary:"); for(int i = 0; i < m; i++) { for(int j = 0; j < n; j++) { System.out.print(binary[i][j].value() + " "); } System.out.println(); } System.out.println(); */ } solver.endSearch(); // Statistics System.out.println(); System.out.println("Solutions: " + solver.solutions()); System.out.println("Failures: " + solver.failures()); System.out.println("Branches: " + solver.branches()); System.out.println("Wall time: " + solver.wallTime() + "ms"); } public static void main(String[] args) throws Exception { int base = 2; int n = 3; int m = 8; if (args.length > 0) { base = Integer.parseInt(args[0]); } if (args.length > 1) { n = Integer.parseInt(args[1]); m = (int) Math.pow(base, n); } if (args.length > 2) { int m_max = (int) Math.pow(base, n); m = Integer.parseInt(args[2]); if (m > m_max) { System.out.println("m(" + m + ") is too large. Set m to " + m_max + "."); m = m_max; } } DeBruijn.solve(base, n, m); } }